from a point 60√3 metre away from the foot of a tower the angle of deviation to the top of the tower is 30°find the height of the tower
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Answer:
Tan x = opposite / adjacent
tan 30= h/60(√3)
1/√3=h/60√3
so h= 60/3 = 20
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Solution: Hence the height of the tower is 60 metre
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