Question

From a point in the interior of an equilateral triangle perpendiculars are drawn on three sides. The lengths of perpendiculars are 14 cm 10 cm and 6 cm find the area of the triangle.​

Answer 1

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Answer 2

Step-by-step explanation:

Area of ∆CPA

∆ABC is an equilateral triangle.Let ABC be equilateral triangle of side 'a' cm. Let P be a point in the interior of the ∆ABC. so PQ⊥BC, PR⊥CA and PS⊥AB So PS = 14 cm, PQ = 10 cm and PR = 6 cm Area of ∆ABC = Area of ∆APB + Area of ∆BPC + Area of ∆CPA