Math, asked by satendrapaswankumar, 4 months ago

from a point in the interior of an equilateral triangle, perpendicular are drawn on the three sides. the lengths of the perpendicular are 8 cm,10 cm and 11 cm. find the area of the triangle carrect to two decimal places. take √3 = 1.73.

Answers

Answered by taqueerizwan2006

Step-by-step explanation:

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For an equilateral triangle of side a cm , the area is 12a×a×sin60∘=3√4a2 cm2 .

This triangle is divided into three triangles each with a base length of a and perpendicular heights of 8,10 and 11 cm respectively. So the total area is 12×a×8+12×a×10+12×a×11=14.5a cm2 .

So 3√4a2=14.5a

3√4a=14.5

a=583√ cm

Therefore, the area is 14.5×583√=485.55 cm2 .

Check: 3√4×(583√)2=485.55 cm.

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from a point in the interior of an equilateral triangle, perpendicular are drawn on the three sides. the lengths of the perpendicular are 8 cm,10 cm and 11 cm. find the area of the triangle carrect to two decimal places. take √3 = 1.73.​

Answers

from a point in the interior of an equilateral triangle, perpendicular are drawn on the three sides. the lengths of the perpendicular are 8 cm,10 cm and 11 cm. find the area of the triangle carrect to two decimal places. take √3 = 1.73.