From a point in the interior of an equilateral triangle the perpendicular distance of the sides are √3 cm,2√3 cm and 5√3cm.The perimeter of triangle is
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Let each side of the equilateral triangle be a.
As shown in the above image, consider the perpendicular distances as
OS = x
OU = y
OT = z
Area of the equilateral triangle PQR =
√3a^2/4 ------------(1)
Area of triangle POQ = 12× PQ × OS = ax2 ------------(2)
Area of triangle POR = 12 × PR × OU
= ay 2 ------------(3)
Area of triangle QOR = 12 × QR × OT
= a2
------------(4)
Area of triangle PQR = (Area of triangle POQ + Area of triangle POR + Area of triangle QOR)√3a^2/4
=ax^2+ay^2+az^2
√3a^2/4
=x^2+y^2+z^2
√3a^/4
=*x+y+z)^2
a = 2√3(x+y+z) ---- (A) .
This can be used as a general formula for such questions.
Applying the given values,
a = 2√3(x+y+z)
=2√3(√3+2√3+5√3)
=2(1+2+5)
= 16 cm
perimeter = 3a = 48 cm
Hope this helps you ✌️✌️☺️☺️❤️
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