Question

from a point of the ground the angle of elevation of bottom and top of a transmission tower fixed on the top of a 20 m high building are 45* and 60* respectively. Find the height of the tower.

Answer 1

tan 45 = BG / OG = 20 / OG

or, 1 = 20 / OG

so, OG = 20 m

tan 60 = TG / OG = (TB + 20) / OG

So, √3 = (TB + 20) / OG

or, 20√3 = (TB + 20)

or, TB = 20√3 - 20 = 20(√3 - 1) m

So, height of the tower TB is 20×0.732 m

= 14.640 m

Answer 2

$\textbf{Answer is in Attachment !}$