Question

From a point on a cricket ground, the angle of elevation of the top of a tower is found to be 30 degree at a distance of 225m from the tower. On walking 150m towards the tower, again the angle of elevation is found. Find the new angle of elevation and the height of the tower.​

Answer 1

Given distance of elevation angle 30° from the tower AB = 225 m

distance from elevation angle 30° to another point towards tower AD = 150 m

So the distance of second point to tower DB = 225 - 150 = 75 m

Let Height of tower BC = h m

Elevation angle from second point = θ

In ∆ABC , We know

tan 30° = BCAB

13√ = h225 ⇒ h = 2253√ m (Ans)

In ∆DBC

tan θ = BCDB

= 2253√75⇒33√ ⇒3√

So

θ = tan−1(3√)

= 60°

Answer 2

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