Question

From a point on level ground, the angle of elevation of the top of a tower is 30° . If the tower is 100 m high, how far is p from the foot of the tower ?​

Answer 1

Answer:

173 m

Step-by-step explanation:

Let AB be the tower.

Then, ∠APB=30

∘

and AB=100 m.

AP

AB

=tan30

∘

=

3

1

⇒AP=(AB×

3

)m

=100

3

m

=(100×1.73)m

=173 m.

solution