Question

from a point on the ground 18m away from the base of a pole, the
angle of elevation at the top of the pole is found to be 45° . Find the height of the pole ....... Plzz answer me first​

Answer 1

Answer:

18m away / 45° inclination.

Let the height of pole be h m

so AB=hm

Distance of the point from

base of pole = 18m

CB=18m

Angle of elevation =45 °

∠ACB=45°

Since tower is vertical to ground

∠ABC=90°

Now tanC= side opp to angle C

___________________

side adjacent to angle C

tanC= AB/CB

tan45= AB/CB

1= H/18

H= 18

Hence height of tower = 18m