Question

From a point on the ground, 20 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is 60°, what is the height of the tower?

Answer 1

Answer:

apply the formula tan60=

$\sqrt{3}$

Answer 2

The height of tower is 34.64  meters

Step-by-step explanation:

Given as :

The angle of elevation of top of tower on ground = 60°

The distance from the foot of tower to elevation = x = 20 meters

Let The height of tower = h meters

According to question

Tan angle = $\dfrac{perpendicular}{base}$

from figure

Tan 60°  = $\dfrac{OB}{OA}$

√3  = $\dfrac{h}{x}$

h = √3 x

Or,  h = 20 √3

Or, height = h = 34.64 meters

Hence, The height of tower is 34.64  meters Answer