Question

From a point on the ground, 30m away from the foot of the tower the angle of elevation of the top of the tower is 30 degree, then find the height of the tower.

Answer 1

SOLUTION ☺️

Let the height of the pole (AB) = h

Length of the shadow (AC) = 30m

Let theta denotes the angle of elevation.

In ∆ABC, tan theta = AB/AC

=) tan 30°= h/30

=) 1/√3= h/30

=) √3h= 30

=) h= 30/√3 × √3/√3 (multiply both sides √3)

=) 30√3/3

=) h= 10√3

hope it helps ✔️

Answer 2

Lets take height of tower is H

So Tan 30°=H/30

So

H= 10√3m