Question

From a point on the ground 40m away from the foot of tower , the angle of elevation of top of a tower is 30° . the angle of elevation of the top of a water tank ( on the top of tower) is 45° . find :

(1) : the height of the tower
(2): the depth of the tank

Answer 1

let h m be the height of tower and m be the depth of tank .

Now, in ΔABC:

tan30°=BC/AB;

1/√3=h/40;

h=40/√3 m (1)

In ΔABD:

tan45°=DC+BC/AB;

1=x+h/40;

x+h=40;

using (1):

x+40/√3=40;

x=40(1-1/√3) m

Then height of the tower = 40/√3 m,

and depth up tank :

40(1-1/√3)m

Answer 2

Answer:

Step-by-step explanation: