Question

from a point on the ground the angle of elevation of the bottom and top of a transmission Tower fixed at the top of a 20 m high building are 45 degree and 60 degree respectively find the height of the tower​

Answer 1

Step-by-step explanation:

Given from a point on the ground the angle of elevation of the bottom and top of a transmission Tower fixed at the top of a 20 m high building are 45 degree and 60 degree respectively find the height of the tower  

• Let the building be PQ and tower be RP
• So height of the building is 20 m.
• So PQ = 20 m
• Let point of ground be A
• Now angle of elevation from point A to bottom of tower is 45 degree
• So angle PAQ = 45 degree
• Angle of elevation from point A to top of tower R = 60 degree
• So angle RAQ = 60 degree
• We need to find PR
• Now angle PQA = 90 degree
• So from triangle PAQ we have
• tan theta = opp side / adj side
• tan A = PQ / AQ
• tan 45 = 20 / AQ
•   1 = 20 / AQ
• Or AQ = 20 m
• Similarly from triangle RAQ
•          tan A = QR / AQ
•          tan 60 = QR / AQ
•           √3 = QR / 20
•             QR = 20 √3
•  Now PQ + PR = 20√3
•            20 + PR = 20√3
•         PR = 20√3 – 20
•         PR = 20 (√3 – 1) m
• Therefore the height of the tower = PR = 20 (√3 – 1) m

Reference link will be

https://brainly.in/question/5829894

Answer 2

hope it helps

mark my answer as brainlist answer