Question

From a point on the ground, the angle of elevation of the top of a tower is observed to be 60°. From a point 40 m vertically above the first 300 AC point of observation, the angle of elevation of the top of the tower is 30°. Find the height of the tower and its horizontal distance from the point of observation




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Answer 1

Answer:

answer tan30°=AB/BE so hight of the tower is60m and the harizondal distance is 20√3

Answer 2

• thanks for giving me lots of thnxx

• tan 30° = AB/BE. So height of the tower is 60m and the horizontal distance is 20√3