Question

From a point on the ground, the angles of elevation of the bottom
and the top of a transmission tower fixed at the top of a 30 m
high building are 45° and 60° respectively. Find the height of the tower​

Answer 1

Answer:

Height of the tower = 30(√3 - 1) m

Step-by-step explanation:

Let BC be the height of the building = 30 m

and AB be the height of the tower.

In ∆BCD

tan45° = BC / CD

CD = BC = 30 m

In ∆ACD

tan60° = AC / CD

√3 x CD = AC

30√3 = AB + BC

AB = (30√3 - 30) m

AB = 30(√3 - 1 ) m

Answer 2

here is your answer mate✔