From a point on the ground, the angles of elevation of the bottom and the top of a
transmission tower fixed at the top of a 20 m high building are 45° and 60° respectively. Find the height of the tower.
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Let BC be the 20 m high building
D is the point on the ground from where the elevation is taken.
Height of transmission tower = AB = AC – BC
To Find: AB, Height of the tower
From figure, In right ΔBCD,
tan 45° = BC/CD
1 = 20/CD
CD = 20
Again,
In right ΔACD,
tan 60° = AC/CD
√3 = AC/20
AC = 20√3
Now, AB = AC – BC = (20√3-20) = 20(√3-1)
Height of transmission tower = 20(√3 – 1) m.
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Answered by
23
Answer:
Let BC be the 20 m high building
D is the point on the ground from where the elevation is taken.
Height of transmission tower = AB = AC – BC
To Find: AB, Height of the tower
From figure, In right ΔBCD,
tan 45° = BC/CD
1 = 20/CD
CD = 20
Again,
In right ΔACD,
tan 60° = AC/CD
√3 = AC/20
AC = 20√3
Now, AB = AC – BC = (20√3-20) = 20(√3-1)
Height of transmission tower = 20(√3 – 1) m.
hope this helps you
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