From a point on the ground, the angles of elevation of the bottom and the top of
transmission tower fixed at the top of a 20 m high building are 45° and 60°
Find the height of the tower.
respectively.
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Answered by
0
Let DC be the tower and BC be the building. Then,
∠CAB=45
o
,∠DAB=60
o
,BC=20 m
Let height of the tower, DC=h m.
In right △ABC,
tan45
o
=
AB
BC
1=
AB
20
AB=20 m
In right △ABD,
tan60
o
=
AB
BD
3
=
20
h+20
h=20(
3
−1) m.
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here is your answer mate✔✔
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