Question

from a point on the ground, the angles of elevation of there's bottom and the top of the transmission tower fixed at the top of a 20 metre high building are 45degree and 60 degree respectively. find the height of the tower

Answer 1

Hello,

Let AB and BC be the transmission tower and Building and D be the point of observation.

Given BC = 20 metres. Let AB = h metres.
Now
∠BDC = 45° and ∠ADC = 60°

In ΔBDC

tan 45°=BC/DC;
1=20/DC;
DC=20 cm

Now in ΔADC:
tan 60°=AC/DC=AB+BC/DC;
√3=h+20/20;
20√3=h+20;
h=20√3-20=20(√3-1)

the height of the tower is 20 (√3-1) metres.

bye :-)

Answer 2

Answer:

Step-by-step explanation: