From a point on the ground the top of a tree is seen to have an angle of elavation 60.the distance between the piont is 50 m. the height of the tree is
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3
Sin 60=h/50
=>√3/2=h/50
=>h=25√3
=>√3/2=h/50
=>h=25√3
Answered by
1
Sin= 60h/50
Underoute 3/2 = H/50
H= 25Underoute 3.
Underoute 3/2 = H/50
H= 25Underoute 3.
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