Question

From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point P from the foot of the tower is:

Answer 1

tan 30°=100/distance
1/root3=100/distance
distance =100root 3
=100×1.732
=173.2m

Answer 2

Let AB be the tower.
Then, APB = 30º and AB = 100 m.
AB/AP=tan 30º=1/√3
⇒ AP = (AB × √3)m
          = 100√3m
          = (100 × 1.73)m
          = 173m