Question

From a point P on the ground, the angles of elevation of the top of a 10 m tall building and a helicopter, hovering at some height vertically over the top the building are 30 and 60 respectively. Find the height of the helicopter above the ground.

Answer 1

We are given the height of the tower 10m and let the height of helicopter be x

We are given angles as 30 and 60. With the TAN function we can find the value by putting the corresponding values

Have a good day

Answer 2

Given: height of building is 10m. The angle of elevation at the top of building is 30° and helicopter is 60°.

To find: height of helicopter above ground.

Step-by-step explanation:

Step 1 of 2

In ΔABC, $tan30^{o} =\frac{P}{B}$

$\frac{1}{\sqrt{3}} =\frac{BC}{AB} \\\frac{1}{\sqrt{3}} =\frac{10}{AB} \\AB=10\sqrt{3}m$

Step 2 of 2

In ΔABD, $tan60^{o} =\frac{P}{B}$

$\sqrt{3} =\frac{DB}{AB} \\\\\sqrt{3}=\frac{DB}{10\sqrt{3}} \\DB=10\sqrt{3}*\sqrt{3}\\DB=30m$

The height of helicopter above the ground in 30m.