From a point P perpendiculars PM and PN are drawn upon x, y axes respectively. If MN passes through a fixed point (a, b) then the locus of P is
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0ahkb0111∣∣∣∣∣∣∣∣=0(∵(o,k),(a,b),(h,o)are collinear)
−k(a−h)+1(0−bh)=0
kh=bh+ak
xy=bx+ay
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