Question

From a point P which is at a distance of 10 cm from the centre O of the circle of

radius 6cm, the pair of tangents PQ and PR to the circle drawn. Find the area

of quadrilateral PQOR.
​

Answer 1

Answer:

Since △ABO is congruent to △ACO, area of ABOC is twice the area of △ABO.

In △ABO, OA=10cm, OB=6cm.

Since tangent is perpendicular to radius at the point of contact, by Pythagoras' theorem, we have

AB=

OA

2

−OB

2

=8cm

So, the area of △ABO is

2

1

×AB×OB=24cm

2

So, the area of ABOC is 2×24=48cm

2

.

So option B is the right answer.