Math, asked by gangotri77, 7 months ago

from a point Q length of the tangent to a circle is 24cm and the tangent of a Q from the centre is 25cm, The radius of a circle is??​

Answers

Answered by Anonymous
18

Let O be the centre of a circle ,from an external

point Q ( such that OQ =25 cm. ) a tangent ( QP

=24 cm ) is drawn. Join O to P. OP is the radius of the circle. Angle OPQ =90°.

In right angled triangle OPQ

OP^2+PQ^2=OP^2

r^2+24^2=25^2

r^2 =625–576= 49

r =7 cm. ,

Answered by Anonymous
0

A tangent is perpendicular to the radius through the point of contact.Using Pythagoras theorem, in ∆OTQ,we have

\longrightarrow\large\tt\red{ {OT}^{2}  =  {OQ}^{2}  -  {QT}^{2} }

\longrightarrow\large\tt\purple{{(25)}^{2}  -  {(24)}^{2} }

\longrightarrow\large\tt\green{625-576}

\longrightarrow\large\tt\blue{49}

\large\sf\pink{Hence,the\:option(A)\:is\:correct}

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