Question

from a point Q the length of a tangent to a circle is 24 cm and the distance of Q from the centre is 25 CM the radius of the circle is​

Answer 1

Step-by-step explanation:

point Q length of atrangular to a circle is =24cm

and

the distance of Q from the center is

= 25cm

atq_

24×25

=49

the radious of a circle is 49cm

Answer 2

Step-by-step explanation:

$\huge\boxed\pink{Question }\dag$

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From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from

centre is 25 cm. The radius of the circle is______

_____________________________

$\huge\boxed\blue{Answer}\dag$

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$\huge\green{Given}$

O is the centre of the circle

PQ is the tangent

PQ =2 4cm & OQ = 25 cm

by theorem : The tangent at any point of a circle is perpendicular to the radius through the point of contact.

OP perpendicular to PQ

by applying pythagoras theorem

$(OQ^ {2})$ = $(OP^ {2}$+$(PQ^ {2})$

$(25^{2})$=$(OP^ {2})$+$(24 ^{{2}})$

625=$(OP^{2}$ +576)

=625-576=$(PO^{2})$

=49

So PQ= $\sqrt{49}$

=7cm is the radius

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Thus we got your answer