From a point Q, the length of the tangent to a circle is 24 cm. and the distance of Q from the centre is 25 cm. The radius of the circle is ?
( a ) 7 cm
( b ) 12 cm
( c ) 15 cm
( d ) 24.5 cm
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༒ Qυєѕтiσи ༒
╔════════◄••❀••►════════╗
From a point Q, the length of the tangent to a circle is 24 cm. and the distance of Q from the centre is 25 cm. The radius of the circle is ?
( a ) 7 cm
( b ) 12 cm
( c ) 15 cm
( d ) 24.5 cm
╚════════◄••❀••►════════╝
★彡 Sσℓυтiσи 彡★
✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏
۩ Refer the image first ۩
O - centre of the circle
OP - a circle radius = ?
OQ = 25 cm
PQ = 24 cm
ᴀᴘᴘʟʏɪɴɢ ᴘʏᴛʜᴀɢᴏʀᴀs ᴛʜᴇᴏʀᴇᴍ
⟹ OQ² = OP² + PQ²
⟹ 25² = OP² + 24²
⟹ OP² = 625 -576
⟹ OP² = 49
⟹ OP = √49
⟹ OP = 7
⛬ The radius of the circle is 7cm.
✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏
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First, draw a perpendicular from the center O of the triangle to a point P on the circle which is touching the tangent. This line will be perpendicular to the tangent of the circle.
So, OP is perpendicular to PQ i.e. OP ⊥ PQ
From the above figure, it is also seen that △OPQ is a right angled triangle.
It is given that
OQ = 25 cm and PQ = 24 cm
By using Pythagoras theorem in △OPQ,
OQ2 = OP2 +PQ2
(25)2 = OP2+(24)2
OP2 = 625-576
OP2 = 49
OP = 7 cm
So, option A i.e. 7 cm is the radius of the given circle
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