From a point Q the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25cm.The radius of the circle is
(a) 7cm
(b) 12cm
(c) 15cm
(d) 24.5cm
please answer me step by step ........
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Answered by
2
Answer:
(d) is the answer for your question
Answered by
1
Answer:
Let O be the centre of the circle .
Given that :
OQ - 25 CM , PQ - 24 CM
As the radius is perpendicular to the tangent at the point of contact ,
Therefore OP Is perpendicular to PQ
Application of Pythogoras Theorem :
OP square + PQ square = OQ square
OP square + 24 square = 25 square
OP square = 625 - 576
OP square = 49
OP = 7
Hence , The radius of the circle is 7 cm .
( A ) 7 cm . Is the correct answer .......
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