From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is
(A) 7 cm (B) 12 cm
(C) 15 cm (D) 24.5 cm
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Let QP be the tangent, such that, Point of contact is P.
Length of the tangent to a circle = 24cm
$$PQ=24cm$$
Let O be the centre of the circle.
OQ=25cm
We have to find the radius OP
Since QP is tangent
OP perpendicular to QP (Since, Tangent is Perpendicular to Radius at the point of contact)
So, ∠OPQ=90∘
So apply Pythogoras theorem to right triangle, OPQ;
➧OP² =OQ² −PQ²
➧OP² =25² −24²
➧OP² =49cm
➧OP= √49
OP=7cm
option A is the answer
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