from a point q , the length of the tangent to a circle is 24cm and the distancecof Q from the centre is 25 cm .The radius of the circle is..
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Step-by-step explanation:
Let QP be the tangent, such that, Point of contact is P.
Length of the tangent to a circle = 24cm
$$PQ=24cm$$
Let O be the centre of the circle.
OQ=25cm
We have to find the radius OP
Since QP is tangent
OP perpendicular to QP (Since, Tangent is Perpendicular to Radius at the point of contact)
So, ∠OPQ=90
∘
So apply Pythogoras theorem to right triangle, OPQ;
OP
2
=OQ
2
−PQ
2
OP
2
=25
2
−24
2
OP
2
=49cm
OP=
49
OP=7cm
hope you understand it bro do hardwrok all the best
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