Question

from a point q the length of the tangent to a circle is 8 cm and the distance of the q from the centre is 10 cm .find the radius of the circle

Answer 1

Answer:

6cm

Step-by-step explanation:

IN∆OPQ

OQ^2=OP^2+PQ^2

10^2=OP^2+8^2

100=OP^2+64

100-64=OP^2

36=OP^2

6=OP

RADIUS IS 6 CM

Answer 2

Answer:

Step-by-step explanation:

In the figure :

Tangent QP= 8 cm

OQ=10 cm

In the right triangle OPQ

$OP^2=OQ^2-PQ^2\\\\=10^2-8^2\\\\=100-64\\\\=36=6^2\\\\\bf { Thus \ r=OP=6 cm}$