Question

From a point with in an equilateral perpendicular are drawn to the three sides and are 5, 7, 9 cm the length the perimeter of the triangle is cm

Answer 1

Answer:

arΔABC=arΔOBC+arΔOCA+arΔOAB

4

3

×x

2

=

2

1

×x×6+

2

1

×x×7+

2

1

×x×8

4

3

x

2

=3x+3.5x+4x

4

3

x

2

=10.5x

x=

3

10.5x×4

=

3

42

3

=14

3

cm