Question

From a quadratic equation if its root are 1/2 and -3/4​

Answer 1

Answer:

Step-by-step explanation:

Roots of quadratic equation is 1/2 & -3/4 quadratic equation is (x-1/2)(x+3/4)= x^2+ 3/4x-x/2-3/8 x^2+x/4-3/8

Answer 2

The quadratic equation is $8x^2+2x-3=0$.

Step-by-step explanation:

It is given that the roots of a quadratic equation are $\dfrac{1}{2}$ and $\dfrac{-3}{4}$.

The general form of quadratic equation is given by :

$x^2-(\text{sum of roots})x+\text{products of roots} =0$ ......(1)

Finding the sum of roots : $\dfrac{1}{2}+\dfrac{-3}{4}=\dfrac{-1}{4}$

Finding the product of roots : $\dfrac{1}{2}\times \dfrac{-3}{4}=\dfrac{-3}{8}$

Putting the above values in equation (1).

$x^2-(\dfrac{-1}{4})x+\dfrac{-3}{8} =0$

$x^2+\dfrac{x}{4}-\dfrac{3}{8}=0\\\\\dfrac{8x^2+2x-3}{8}=0\\\\8x^2+2x-3=0$

So, the quadratic equation is $8x^2+2x-3=0$.

Learn more,

Quadratic equation

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