Question

From a quadratic equation whose roots are 2 and 3 respectively

Answer 1

Let ,

$\alpha = 2 \\ \beta = 3$

Hence,

$\alpha + \beta = 2 + 3 = 5 \\ \alpha \times \beta = 2 \times 3 = 6$

Therefore,

${x}^{2} - ( \alpha + \beta )x + ( \alpha \times \beta ) = 0$

By putting values,

we get,

${x}^{2} - 5x + 6 = 0$

This is your answer

Hope it helps you

Answer 2

Here your answer mate▫

$\alpha + \beta = 3 + 2 = 7 \\ \alpha \times \beta = 3 \times 2 = 10$
Quadratic equation is
$x {}^{2} ( \alpha + \beta )x + \alpha + \beta = 0$
x²+7x + 10 =0
here is your quadratic equation