Question

from a quadratic equation whose roots are -3 and 4​

Answer 1

$\huge\tt{\red{\underline{Given:}}}$

★ -3 & 4 are the roots of a quadratic equation.

$\huge\tt{\red{\underline{To\:Find:}}}$

★The quadratic equation whose roots are given.

$\huge\tt{\red{\underline{Answer:}}}$

The quadratic whose roots are $\alpha$ & $\beta$ can be written as ,

$\large\green{\boxed{ x^{2} -x(\alpha+\beta) +\alpha \beta = 0}}$

=

Let $\alpha = -3 \:\: and \:\:\beta=4$

$\implies x^{2} -x(\alpha+\beta) +\alpha \beta = 0$

$\implies x^{2}-x (-3+4)+(-3\times 4)=0$

$\implies x^{2}- x \times 1 -12=0$

.°. ${\underline{\boxed{x^{2}-x -12=0}}}$

Therefore the required quadratic equation is $x^{2}-x -12=0$.

$\huge\purple{\boxed{ x^{2}-x -12=0}}$