Question

from a quadratic polynomial p(x) with -1/6 and -1/3as the sum and product of its zeroes​

Answer 1

Given,

alpha + beta= -b/a

-1/6= -b/a

b/a= 1/6----------(1)

And,

alpha× beta = c/a

-1/3= c/a

c/a= -1/3---------------(2)

From equation (1) and (2),we get,

a= 6

b= 1

c= -2

So, the required polynomial= ax2 + bx+ c

= 6x2+ x-2

Answer 2

Quadratic polynomial=k [x^2 - (sum of zeroes)x + (product of zeroes) ]

Where k is a non- zero real number

Here

Quadratic Polynomial is

p(x)= K [x^2 -(-1/6)x+(-1/3)

p(x)=K [x^2+1/6x-1/3]

Here Lcm of 6, 3=6

-->

So the polynomial p(x)= K/6 [6x^+2x-2]