Question

From a quadratic polynomial p(x) with 3 and -2/5 as sum of products of zeroes

Answer 1

Answer:

x²+15x-2

Step-by-step explanation:

sum of roots = 3

product of roots = -2/5

polynomial = k{ x² + (sum)x - prouduct}

                     = k{ x²+ 3x +2/5}

                      = k{ 5x² + 15x + 2/5)

Let k = 5

so, polynomial = x²+15x-2

Hope it will help you......

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Answer 2

Answer:

$\large p(x)=5x^2-15x-2$

Step-by-step explanation:

Given :

Sum and products of zeroes are 3  and  - 2 / 5 respectively.

We know for Required plynomial as

$\large \text{p(x)= x^2-(sum \ of \ zeroes)x+(products \ of \ zeroes) }$

Now put the values here we get

$\large \text{p(x)= x^2-(3)x+(-2/5) }\\\\\\\large \text{p(x)= x^2-3x-2/5 }\\\\\\\large \text{Now divide the p ( x ) \ by \ 5 we get}\\\\\\\large p(x)=5x^2-15x-2$

Thus we get answer.