Math, asked by kumarashwani5605, 10 months ago

from a quadratic polynomial whose zeroes are 3 and -2​

Answers

Answered by BrainlyTornado
1

(x - 3)(x + 2) =  {x}^{2}  - 3x + 2x - 6

 =  {x}^{2}  - x - 6

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Answered by pulakmath007
18

\displaystyle\huge\red{\underline{\underline{Solution}}}

FORMULA TO BE IMPLEMENTED

If the zeroes of the quadratic polynomial are given, then the quadratic polynomial is obtained as

 {x}^{2}  - ( \: sum \: of \: the \: zeros \: )x + product \: of \: the \: zeros \:

GIVEN

A quadratic polynomial, whose zeroes are 3 and -2

TO DETERMINE

The quadratic polynomial

EVALUATION

The Zeros are 3 & - 2

So

Sum of the zeroes

= 3 + (-2)

= 3 - 2

= 1

Product of the Zeros

= 3 × (-2)

= - 6

So the required polynomial is

 {x}^{2}  - ( \: sum \: of \: the \: zeros \: )x + product \: of \: the \: zeros \:

 =  {x}^{2}  - x - 6

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