Question

from a quadratic polynomial whose zeroes are -6 and -2/3​

Answer 1

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Answer:

3x^2 - 20x + 12 = 0

Step-by-step explanation:

sum of zeroes (a+b) = -6 + (-2/3) = -20/3

product of zeroes (ab) = -6 × -2/3 = 4

we know the formula of quadratic polynomial

x^2 + (a+b)x + (ab) = 0

x^2 - 20/3x + 4 = 0

3x^2 - 20x + 12 = 0

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