Question

from a quadratic polynomial whose zeros and 3 + under root 2 and 3 minus under root 2​

Answer 1

Step-by-step explanation:

let

$3 + \sqrt{2 \ }$

$3 - \sqrt{2}$

given roots

equation

sum of roots=6

product of roots=7

x^2-(sum of roots)x+(product of roots)

x^2-6x+7=0...