Question

from a quadratic polynomial whose zeros are as follows 2 + under root , 2 - under root 3​

Answer 1

Step-by-step explanation:

$if \: zeros \: are \: 2 - \sqrt{3} \: and \: 2 + \sqrt{3} \: \\ then \: sum \: of \: the \: roots \: = 2 + \sqrt{3} + 2 - \sqrt{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4 \\ products \: of \: roots = (2 + \sqrt{3} )(2 - \sqrt{3} ) \\ = 1 \\ equation \: \\ {x}^{2} - 4x + 1 = 0$

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