Question

from a quadratic polynominal whose sum of zeros is -4 and produet of zeros is 8​

Answer 1

Answer:

sum of zeroes= -4 (alpha a)

product of zeroes = 8 (beta b)

a + b = -b/a

a × b = c/a

-4 + 8 = -b/a

b = 4 and a = 8 (-b= -4 = 4)

-4 × 8 = c/a

a = 8 and c = -4

so, a= 8 b= 4 and c = -4

so quadratic polynomial is

8x2 + 4x - 4 =0

hope this answer will be right......

Answer 2

Answer: x² + 4x + 8 = 0 is the required Quadratic Polynomial.

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Step-by-step explanation:

Let the zeros of polynomial be 'a' and 'b',

a + b = -4  ----eqn.1

a * b = 8  -----eqn.2

The General form of a Quadratic Polynomial is

x² - (Sum of zeros) x + (Product of zeros) = 0

x² - (a + b) x + (a*b) = 0

==> x² -(-4)x + 8 = 0

==> x² + 4x + 8 = 0

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