from a rectangular metal of sheet of length 11 cm and breadth 8 CM , three circular plates of radii 3 CM and 2 CM and 1 cm are cut thr area of the remaining part ( in cm2) is equal to the area of the new circle . the area of thr new circle (in cm2) is
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AREA OF RECTANGULAR METAL SHEET=(11×8)cm²
=88cm²
AREA OF FIRST CIRCLE=π r²
=22/7 × (3)²
=22/7 × 9
=198/7cm²
AREA OF SECOND CIRCLE=π r²
=22/7 × (2)²
=22/7 × 4
=88/7cm²
AREA OF THIRD CIRCLE=π r²
=22/7 × (1)²
=22/7 × 1
=22/7
THEREFORE,TOTAL AREA COVERED BY THREE CIRCLES={(198/7)+(88/7)+(22/7)}cm²
={(198+88+22)/7}cm²
=308/7cm²
=44cm²
THEREFORE,AREA OF REMAINING PART=(88‐44)cm²
=44cm²
As per question,
AREA OF THE REMAINING PART=AREA OF NEW CIRCLE
THEREFORE,AREA OF NEW CIRCLE=44cm²
ANSWER:–
AREA OF NEW CIRCLE=44cm²
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