From a rectangular region ABCD with AB=20cm,a right triangle AED with AE=9cm and DE=12cm,is cut off. On the other end, taking BC as diameter, a semicircle is added on outside the region. Find the area of the shaded region. (Use π=22/7).
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in triangleAED
ON APPLYING PYTHAGORAS THEORUM
AD=25cm
Area of rect ABCD = l×b=25×20=500cm^2
Area of triangle =1/2×b×h
for finding height draw a perpindicular from point E to line AD
#height = by pythagoras theorum
Area of semicircle= 1/2 πr^2
where pie=22/7
r =BC/2=25/2=12.5Cm
area of shaded portion =area ofABCD-area ofAED+ Area of semicirle.
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