From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper (use π = 22/7)
Answers
Answer:
Area of remaining paper = 1120 – 308 = 812 cm2
Step-by-step explanation:
Length of paper, AB = l = 40cm
Width of paper, AD = b = 40cm
Area of paper = l × b = 40 × 28 = 1120 cm2
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2. πr2
= 1/2 × 22/7 × 14 × 14
= 308cm2
∴ Area of remaining paper = 1120 – 308 = 812 cm2
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Answer:
Consider the figure,
AD = 28cm
BC/2 = r = 14cm
AB = 40cm
Length of paper, AB = l = 40cm
Length of paper, AB = l = 40cmWidth of paper, AD = b = 28cm
Length of paper, AB = l = 40cmWidth of paper, AD = b = 28cmArea of paper = l × b = 40 × 28 = 1120 cm^2
2Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2. πr^2
2 = 1/2 × 22/7 × 14 × 14
2 = 1/2 × 22/7 × 14 × 14 = 308cm^2
∴ Area of remaining paper,
= 1120 – 308
= 812 cm^2
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