Question

From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper $\rm{Use\:\pi= \frac{22}{7}}$​

Answer 1

Answer:

1076 cm^2

Step-by-step explanation:

As it is a rectangle : AD = BC = 28cm

Area of remaining paper

= Area of the rectangle - Area of the semi-circular portion

= L × B - ( πR )

= 40 × 28 - ( 22/7 × 28/2 )

[ Radius = diameter / 2 = 28/2 ]

= 1120 - ( 11 × 4 )

= 1120 - 44

= 1076 cm^2

Answer 2

*Question:—

From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper . Use π = 22/7

*Answer:—

→ Length of rectangular sheet of paper = 40 cm

→ Breadth of rectangular sheet of paper = 28 cm

→ Radius of the semicircular cut out = 14 cm

→ Area of rectangular sheet of paper

→ Area of rectangle = length × breadth

= 40 × 28

= 1120 cm²

Area of semicircular cut out :—

= 1/2 πr2

= 1/2 x 22/7 x 14 x 14

= 308 cm²

Now,

Area of remaining sheet of paper = Area of rectangular sheet of paper – Area of semicircular cut out

= 1120 – 308

= 812

Therefore,

Area of remaining sheet of paper is 812 cm² .

@vikramjeeth.