from a rectangular sheet of paper abcd with ab=40cm and ad=28cm a semicircular portion with bc as diameter is cut off find the area of the remaining paper
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Length of paper, AB = l = 40cm
Width of paper, AD = b = 40cm
Area of paper = l × b = 40 × 28 = 1120 cm2
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2. πr2
= 1/2 × 22/7 × 14 × 14
= 308cm2
∴ Area of remaining paper = 1120 – 308 = 812 cm2
Width of paper, AD = b = 40cm
Area of paper = l × b = 40 × 28 = 1120 cm2
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2. πr2
= 1/2 × 22/7 × 14 × 14
= 308cm2
∴ Area of remaining paper = 1120 – 308 = 812 cm2
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