From a refill of mass 4kg,a bullet of mass 50g is fired with an interracial velocity of 35 m/s. Calculate the innerracial recole velocity of the refill.
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Answers
Given that,
- From a refill of mass 4kg,a bullet of mass 50g is fired with an initial velocity of 35 m/s.
So,
- Mass of refill, M = 4 km
- Mass of bullet, m = 50 g = 0.05 kg
Since, the refill is at rest. So, initial velocity, u = 0 m/s.
We know,
Momentum = Mass × Velocity.
So, Total initial Momentum of the refill and bullet is given by
Let assume that
- Recoil velocity of the refill = V m/s
Given that,
- Velocity of bullet, v = 35 m/s
So,
Total Momentum after bullet is fired is given by
According to Law of Conservation of Momentum,
On substituting the values, we get
Hence,
- The recoil velocity of the refill is 0.4375 m/s.
Explanation:
Given that,
From a refill of mass 4kg,a bullet of mass 50g is fired with an initial velocity of 35 m/s.
So,
Mass of refill, M = 4 km
Mass of bullet, m = 50 g = 0.05 kg
Since, the refill is at rest. So, initial velocity, u = 0 m/s.
We know,
Momentum = Mass × Velocity.
So, Total initial Momentum of the refill and bullet is given by
\rm :\longmapsto\:Initial \: Momentum = (m + M) \times 0 = 0:⟼InitialMomentum=(m+M)×0=0
Let assume that
Recoil velocity of the refill = V m/s
Given that,
Velocity of bullet, v = 35 m/s
So,
Total Momentum after bullet is fired is given by
\rm :\longmapsto\:Total \: Momentum = MV + mv:⟼TotalMomentum=MV+mv
\rm :\longmapsto\:Total \: Momentum = 4 \times V + 0.5 \times 35:⟼TotalMomentum=4×V+0.5×35
\rm :\longmapsto\:Total \: Momentum = 4 V + 1.75:⟼TotalMomentum=4V+1.75
According to Law of Conservation of Momentum,
\red{\rm :\longmapsto\:(M + m)u = MV + mv}:⟼(M+m)u=MV+mv
On substituting the values, we get
\red{\rm :\longmapsto\:0 = 4V + 1.75}:⟼0=4V+1.75
\red{\rm :\longmapsto\:4V = - 1.75}:⟼4V=−1.75
\red{\rm :\longmapsto\:V = - 0.4375}:⟼V=−0.4375
Hence,
The recoil velocity of the refill is 0.4375 m/s.