From a ribbon which is 22 m long two pieces of length 26/ 5 m and 32/10 m are cut off what is the length of the remaining ribbon
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Answered by
53
2 PIECES OF RIBBON ARE 26/5 AND 32/10 THIS IS EQUAL TO 52/10 AND 32/10 LET THE REMAINING PIECE BE X
X+52/10+32/10=22
10X +52+32=22*10
10X+84=220
10X=136
X=13.6M
X+52/10+32/10=22
10X +52+32=22*10
10X+84=220
10X=136
X=13.6M
Answered by
22
Step-by-step explanation:
length of one piece =26/5
length of other piece=32/10
length of remaining piece=
26/5+32/10=(l.c.m=10)
26/5×2=52/10
52/10+32/10=84/10=42/5=13.6
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