from a ribon which is 32 m. long two pieces of length 26/5 m.72/10m. are cut off what is the length of the remaining ribbon
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Answered by
7
Answer:
total length =32m
cut piece= 26/5 and 72/10
total piece cut= 26/5+72/10
LCM=10
52+72/10
=124/10
32-62/5
160-62/5
=98/5
Answered by
5
Answer:
Given that :
Total length= 32m
Cut piece=26/5 and 72/10
Total piece cut = 26/5 + 72/10
LCM=10
52+72/10
=124/10
32-62/5
160-62/5
=98/5
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