Question

From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m s–1 . Calculate the initial recoil velocity of the rifle ...

answer please​

Answer 1

Answer:

-0.4375

Step-by-step explanation:

Mass of the rifle, m1 = 4 kg

Mass of the bullet, m2 = 50g = 0.05 kg

Recoil velocity of the rifle = v1

Bullet is fired with an initial velocity, v2 = 35 m/s

Total mass = m1 + m2 = 4 + 0.05 = 4.05 kg

Since the system was at rest , velocity (v) = 0

Momentum ( before firing ) = mass x velocity = ( m1 + m2 )v = ( 4.05 ) 0 = 0 kg m/s

Total momentum = momentum of bullet + momentum of rifle = m1 v1 + m2 v2

= 0.05 x 35 + 4 x v2 = 7/4 + 4 v2

Since the total momentum remain conserved

Total momentum before firing = Total momentum after firing

0 = 7/4 + 4 v2

4 v2 = - 7/4

v2 = - 7/16

v2 = -04375 m/s

Thus , the recoil velocity of the pistol is -0.4375

m/s .

Hope it helps u

Answer 2

Answer:

momentum of rifle + momentum of bullet

= mass × velocity of rifle = mass × velo. of bullet

mass of bullet = 50/1000 g

total momentum= 0

by law conservation of momentum

0 = mass × velo. of rifle + mass × velo. of bullet

0 = 4 ×(- v )+ 50/1000 × 35

v = 0.43(approx)

Step-by-step explanation:

hope it helps pls pls follow