Question

From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m s–1. Calculate the initial recoil velocity of the rifle.

Answer 1

Answer:

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Answer 2

Given:

The Bullet’s mass (m₁) = 50 g

The rifle’s mass (m₂) = 4kg = 4000g

Initial velocity of the fired bullet (v1) = 35 m/s

To Find:

Initial recoil velocity of the vehicle

Solution:

Let the recoil velocity be v₂.

The initial momentum of the rifle = 0 as the rifle was initially at rest.

The total momentum of the rifle and bullet after firing = m₁v₁ + m₂v₂

the law of conservation of momentum states that" For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied".

Therefore, the total momentum of the rifle and the bullet after firing = 0   m₁v₁ + m₂v₂ = 0

v₂= -$\frac{m_{1} v_{1} }{m_{2} }$

v₂= -$\frac{500_{g}X 35ms_{-1} }{4000g}$

v₂= -0.4375 m/s

Hence, the recoil velocity is -0.4375m/s

[The negative sign before the answer indicates that the recoil velocity is opposite to that of the motion of the bullet.]